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(FAQ) Comparing strings in Java

Q: How come comparing strings in Java with == produces unexpected results?


TL;DR: Use the equals method for comparing strings; i.e. s1.equals(s2) as opposed to s1 == s2. The former compares values whereas the latter compares references.

This is the source of a common problem encountered by many Java beginners; they try to compare two strings via == and are surprised to find that the result is false for two equivalent strings.

The appropriate way to compare string s1 with string s2 is via equals:


It’s important to understand why this is the case. The problem lies in how == works with non-primitive arguments. Specifically, in that it compares references and not values. Two distinct string objects with identical values can be stored in different places, and in the eyes of == these two strings are not the same:

Fig. 1

|  s1  |--------> "abc"

|  s2  |--------> "abc"

(Note that it is important to think of Java variables as pointers; a variable consists of a reference to an object in memory.)

In the above situation, s1 == s2 will result in false since s1 and s2 do not refer to the same object, even though the objects to which they do refer are equal in terms of value. Now, if you had a second case like:

Fig. 2

|  s1  |--------> "abc"
+------+            ^
+------+            |
|  s2  |------------+

then s1 == s2 would in fact be true, since the two variables do refer to the same object.

You can even see this in actual code. Because string literals are interned in a string pool, two equivalent string literals will always refer to the same string instance which is cached inside this pool:

String s1 = "abc";
String s2 = "abc";
System.out.println(s1 == s2);

Here we have the case illustrated in Fig. 2, so the output is true. By contrast, here:

String s1 = "abc";
String s2 = new String("abc");  // distinct instance

System.out.println(s1 == s2)

we have the case depicted in Fig. 1, so the output is false.

In short, if you want to compare two strings by value (which more often than not is the case), you should use the equals method, which goes through the characters of each string one by one to check for equality.