# (FAQ) Dynamic variables

For example:

### A:

TL;DR: You can’t (at least not easily) – you should use an array or collection for this purpose instead.

Something like this is not directly possible in Java because local variable names are merely a convenience for the programmer; they are not kept track of after your code is compiled. You can see this yourself by looking at compiled bytecode (with javap -c). For example:

will become:

ICONST_0
ISTORE 1
ICONST_0
ISTORE 2
GETSTATIC java/lang/System.out : Ljava/io/PrintStream;
INVOKEVIRTUAL java/io/PrintStream.println(I)V


Notice that the names we gave our variables do not show up in the bytecode.

Now, in theory it could be possible to compile your code with the -g option of javac which would cause the .class file to contain all debugging information, including local variable names. You could then extract this data and use it to dynamically access variables. As you can probably imagine, this is more trouble than its worth, and will simply perform poorly (not to mention it relies on the condition that the code was compiled using -g).

The correct way to go about this problem would be to use some sort of collection or an array, depending on the context.

If your “variable names” are linear (e.g. a0, a1, a2 …), then more often than not a List would be most appropriate. Adapting the snippet in the question:

(It goes without saying that in any real code you should use a better name than a.) In any case, the idea is still here; now that we have this list, the a[some_int] above can become a.get(some_int).

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